# Lösungen: Erweitern von Brüchen I (Erweitert)

1. Erweitere die folgenden Brüche mit den vorgegebenen Zahlen:

a)  $$\frac{1}{5}^{\color{blue}{·2}} = \bbox[#e1ffc1,5px]{ \frac{1\color{blue}{·2}}{5\color{blue}{·2}} = \frac{2}{10} }$$

b)  $$\frac{2}{3}^{\color{blue}{·3}} = \bbox[#e1ffc1,5px]{ \frac{2\color{blue}{·3}}{3\color{blue}{·3}} = \frac{6}{9} }$$

c)  $$\frac{2}{7}^{\color{blue}{·4}} = \bbox[#e1ffc1,5px]{ \frac{2\color{blue}{·4}}{7\color{blue}{·4}} = \frac{8}{28} }$$

d)  $$\frac{7}{9}^{\color{blue}{·5}} = \bbox[#e1ffc1,5px]{ \frac{7\color{blue}{·5}}{9\color{blue}{·5}} = \frac{35}{45} }$$

e)  $$\frac{15}{8}^{\color{blue}{·7}} = \bbox[#e1ffc1,5px]{ \frac{15\color{blue}{·7}}{8\color{blue}{·7}} = \frac{105}{56} }$$

f)  $$\frac{1}{7}^{\color{blue}{·7}} = \bbox[#e1ffc1,5px]{ \frac{1\color{blue}{·7}}{7\color{blue}{·7}} = \frac{7}{49} }$$

g)  $$\frac{11}{15}^{\color{blue}{·10}} = \bbox[#e1ffc1,5px]{ \frac{11\color{blue}{·10}}{15\color{blue}{·10}} = \frac{110}{150} }$$

h)  $$\frac{11}{15}^{\color{blue}{·12}} = \bbox[#e1ffc1,5px]{ \frac{11\color{blue}{·12}}{15\color{blue}{·12}} = \frac{132}{180} }$$

i)  $$\frac{10}{9}^{\color{blue}{·9}} = \bbox[#e1ffc1,5px]{ \frac{10\color{blue}{·9}}{9\color{blue}{·9}} = \frac{90}{81} }$$

j)  $$\frac{4}{25}^{\color{blue}{·15}} = \bbox[#e1ffc1,5px]{ \frac{4\color{blue}{·15}}{25\color{blue}{·15}} = \frac{60}{375} }$$

k)  $$\frac{7}{21}^{\color{blue}{·12}} = \bbox[#e1ffc1,5px]{ \frac{7\color{blue}{·12}}{21\color{blue}{·12}} = \frac{84}{252} }$$

l)  $$\frac{9}{11}^{\color{blue}{·19}} = \bbox[#e1ffc1,5px]{ \frac{9\color{blue}{·19}}{11\color{blue}{·19}} = \frac{171}{209} }$$

2. Erweitere die Brüche gemäß folgender Tabelle:

 Erweitere mit 2 mit 3 mit 4 $$\frac{8}{24}$$ $$\frac{16}{48}$$ $$\frac{24}{72}$$ $$\frac{32}{96}$$ $$\frac{12}{48}$$ $$\frac{24}{96}$$ $$\frac{36}{144}$$ $$\frac{48}{192}$$ $$\frac{48}{60}$$ $$\frac{96}{120}$$ $$\frac{144}{180}$$ $$\frac{192}{240}$$ $$\frac{36}{80}$$ $$\frac{72}{160}$$ $$\frac{108}{240}$$ $$\frac{144}{320}$$