Lösungen: Kürzen von Brüchen II (Basis)

1. Bestimme die Zahl, die zum gekürzten Bruch führt:

a) \( \frac{2}{4}^{\bbox[#e1ffc1,5px]{:2}} = \frac{2\color{blue}{:2}}{4\color{blue}{:2}} = \frac{1}{2} \)

b) \( \frac{3}{6}^{\bbox[#e1ffc1,5px]{:3}} = \frac{3\color{blue}{:3}}{6\color{blue}{:3}} = \frac{1}{2} \)

c) \( \frac{6}{10}^{\bbox[#e1ffc1,5px]{:2}} = \frac{6\color{blue}{:2}}{10\color{blue}{:2}} = \frac{3}{5} \)

d) \( \frac{6}{9}^{\bbox[#e1ffc1,5px]{:3}} = \frac{6\color{blue}{:3}}{9\color{blue}{:3}} = \frac{2}{3} \)

e) \( \frac{12}{4}^{\bbox[#e1ffc1,5px]{:4}} = \frac{12\color{blue}{:4}}{4\color{blue}{:4}} = \frac{3}{1} = 3 \)

f) \( \frac{3}{12}^{\bbox[#e1ffc1,5px]{:3}} = \frac{3\color{blue}{:3}}{12\color{blue}{:3}} = \frac{1}{4} \)

g) \( \frac{8}{16}^{\bbox[#e1ffc1,5px]{:8}} = \frac{8\color{blue}{:8}}{16\color{blue}{:8}} = \frac{1}{2} \)

h) \( \frac{10}{24}^{\bbox[#e1ffc1,5px]{:2}} = \frac{10\color{blue}{:2}}{24\color{blue}{:2}} = \frac{5}{12} \)

i) \( \frac{8}{28}^{\bbox[#e1ffc1,5px]{:4}} = \frac{8\color{blue}{:4}}{28\color{blue}{:4}} = \frac{2}{7} \)

j) \( \frac{25}{60}^{\bbox[#e1ffc1,5px]{:5}} = \frac{25\color{blue}{:5}}{60\color{blue}{:5}} = \frac{5}{12} \)

k) \( \frac{5}{25}^{\bbox[#e1ffc1,5px]{:5}} = \frac{5\color{blue}{:5}}{25\color{blue}{:5}} = \frac{1}{5} \)

l) \( \frac{10}{120}^{\bbox[#e1ffc1,5px]{:10}} = \frac{10\color{blue}{:10}}{120\color{blue}{:10}} = \frac{1}{12} \)

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