Lösungen: Kürzen von Brüchen II (Erweitert)

1. Bestimme die Zahl, die zum gekürzten Bruch führt:

a) \( \frac{8}{40}^{\bbox[#e1ffc1,5px]{:4}} = \frac{8\color{blue}{:4}}{40\color{blue}{:4}} = \frac{2}{10} \)

b) \( \frac{3}{9}^{\bbox[#e1ffc1,5px]{:3}} = \frac{3\color{blue}{:3}}{9\color{blue}{:3}} = \frac{1}{3} \)

c) \( \frac{6}{16}^{\bbox[#e1ffc1,5px]{:2}} = \frac{6\color{blue}{:2}}{16\color{blue}{:2}} = \frac{3}{8} \)

d) \( \frac{8}{48}^{\bbox[#e1ffc1,5px]{:8}} = \frac{8\color{blue}{:8}}{48\color{blue}{:8}} = \frac{1}{6} \)

e) \( \frac{12}{84}^{\bbox[#e1ffc1,5px]{:12}} = \frac{12\color{blue}{:12}}{84\color{blue}{:12}} = \frac{1}{7} \)

f) \( \frac{51}{12}^{\bbox[#e1ffc1,5px]{:3}} = \frac{51\color{blue}{:3}}{12\color{blue}{:3}} = \frac{17}{4} \)

g) \( \frac{909}{54}^{\bbox[#e1ffc1,5px]{:9}} = \frac{909\color{blue}{:9}}{54\color{blue}{:9}} = \frac{101}{6} \)

h) \( \frac{155}{25}^{\bbox[#e1ffc1,5px]{:5}} = \frac{155\color{blue}{:5}}{25\color{blue}{:5}} = \frac{31}{5} \)

i) \( \frac{27}{81}^{\bbox[#e1ffc1,5px]{:9}} = \frac{27\color{blue}{:9}}{81\color{blue}{:9}} = \frac{3}{9} \)

j) \( \frac{30}{195}^{\bbox[#e1ffc1,5px]{:15}} = \frac{30\color{blue}{:15}}{195\color{blue}{:15}} = \frac{2}{13} \)

k) \( \frac{175}{205}^{\bbox[#e1ffc1,5px]{:5}} = \frac{175\color{blue}{:5}}{205\color{blue}{:5}} = \frac{35}{41} \)

l) \( \frac{210}{1020}^{\bbox[#e1ffc1,5px]{:10}} = \frac{210\color{blue}{:10}}{1020\color{blue}{:10}} = \frac{21}{102} \)

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