AB: Bruchmauern II
1.
Bei Bruchmauern addieren wir von unten nach oben. Zwei nebeneinander liegende Felder ergeben in Summe das darüber liegende Feld. Löse die folgenden Aufgaben entsprechend, indem du die Brüche berechnest und in die Kästchen einträgst:
a)
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\( \frac{1}{4} \)
\( \frac{1}{4} \)
\( \frac{1}{4} \)
\( \frac{2}{4} \)
\( \frac{9}{4} \)
\( 1 \)
\( \frac{5}{4} \)
\( \frac{1}{2} \)
\( \frac{1}{2} \)
\( \frac{3}{4} \)
\( \frac{1}{4} \)
\( \frac{1}{4} \)
\( \frac{1}{4} \)
\( \frac{2}{4} \)
b)
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\( \frac{3}{2} \)
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\( \frac{1}{2} \)
\( \frac{3}{4} \)
\( \frac{4}{8} \)
\( \frac{21}{4} \)
\( \frac{11}{4} \)
\( \frac{5}{2} \)
\( \frac{3}{2} \)
\( \frac{5}{4} \)
\( \frac{5}{4} \)
\( 1 \)
\( \frac{1}{2} \)
\( \frac{3}{4} \)
\( \frac{4}{8} \)
c)
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\( \frac{9}{5} \)
\( \frac{2}{5} \)
\( \frac{6}{15} \)
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\( \frac{3}{5} \)
\( \frac{29}{5} \)
\( \frac{12}{5} \)
\( \frac{17}{5} \)
\( \frac{4}{5} \)
\( \frac{8}{5} \)
\( \frac{9}{5} \)
\( \frac{2}{5} \)
\( \frac{6}{15} \)
\( \frac{6}{5} \)
\( \frac{3}{5} \)
d)
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\( \frac{1}{3} \)
\( \frac{1}{2} \)
\( \frac{2}{3} \)
\( \frac{5}{2} \)
\( \frac{19}{3} \)
\( 2 \)
\( \frac{13}{3} \)
\( \frac{5}{6} \)
\( \frac{7}{6} \)
\( \frac{19}{6} \)
\( \frac{1}{3} \)
\( \frac{1}{2} \)
\( \frac{2}{3} \)
\( \frac{5}{2} \)
e)
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\( \frac{4}{2} \)
\( \frac{7}{3} \)
\( \frac{5}{3} \)
\( \frac{5}{2} \)
\( \frac{1}{3} \)
\( \frac{1}{2} \)
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\( 32 \)
\( \frac{31}{2} \)
\( \frac{33}{2} \)
\( \frac{43}{6} \)
\( \frac{25}{3} \)
\( \frac{49}{6} \)
\( \frac{17}{6} \)
\( \frac{13}{3} \)
\( 4 \)
\( \frac{25}{6} \)
\( \frac{5}{6} \)
\( \frac{4}{2} \)
\( \frac{7}{3} \)
\( \frac{5}{3} \)
\( \frac{5}{2} \)
\( \frac{1}{3} \)
\( \frac{1}{2} \)
\( \frac{3}{2} \)
\( \frac{5}{6} \)
\( \frac{5}{6} \)
\( \frac{5}{3} \)