CHECK: Summen

\( \sum \limits_{n=0}^{4} 2^n = 2^0 + 2^1 + 2^2 + 2^3 + 2^4 = 1 + 2 + 4 + 8 + 16 = 31 \)

$$ \sum \limits_{n=0}^{2} \left(\frac12\right)^n = \left( {\frac{1}{2}} \right)^0 + \left( {\frac{1}{2}} \right)^1 + \left( {\frac{1}{2}} \right)^2 = 1 + \frac{1}{2} + \frac{1}{4} = \frac{4}{4} + \frac{2}{4} + \frac{1}{4} = \frac{7}{4} $$

\( \sum \limits_{n=0}^{5} \left( \frac{1}{4}·n+0,25 \right) \\ = \left( \frac{1}{4}·0+0,25 \right) + \left( \frac{1}{4}·1+0,25 \right) + \left( \frac{1}{4}·2+0,25 \right) + \left( \frac{1}{4}·3+0,25 \right) + \left( \frac{1}{4}·4+0,25 \right) + \left( \frac{1}{4}·5+0,25 \right) \\ = 0,25 + 0,5 + 0,75 + 1 + 1,25 + 1,5 = 5,25 \)

\( \sum \limits_{n=1}^{4} \left( 100-3·n \right) = (100-3·1) + (100-3·2) + (100-3·3) + (100-3·4) \\ = 97 + 94 + 91 + 88 \\ = 370 \)